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20x^2+37x-6=0
a = 20; b = 37; c = -6;
Δ = b2-4ac
Δ = 372-4·20·(-6)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-43}{2*20}=\frac{-80}{40} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+43}{2*20}=\frac{6}{40} =3/20 $
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